September 2004 - openSUSE Programming - openSUSE Mailing Lists

Re: [suse-programming-e] Registering another class as a variable in one class (Beginner Question).
by Prabu Subroto 10 Oct '04

10 Oct '04

Dear Paul. I am still confused. Sorry I am a really beginner in GNU C++. 1. May I make 2 classes in one file? 2. header is somewhat like this : "#include <iostream.h>. I am confused how should the header file of my "menu" class for registering "samba" class in the "menu" class? Could you give me an example of the header file of my "menu" class please....? Thank you very much in advance. --- Paul Howie <paulhowie(a)gmail.com> wrote: > You need to pre-declare the class samba. > > Just moving it above the main method should do the > trick, but you > might want to declare it in a header file for > safety. > > Paul > > > On Thu, 30 Sep 2004 05:16:01 -0700 (PDT), Prabu > Subroto > <prabu_subroto(a)yahoo.com> wrote: > > Dear my friends.. > > > > I am practicing GNU C++ on SuSE 9.1. > > > > But if I compile my code I got this error message > as > > below: > > ==== > > patrixlinux@patrix:~/arsip/proyek/gcc/liss> g++ -o > > liss ./liss.cpp > > In file included from > > /usr/include/g++/backward/iostream.h:31, > > from liss.cpp:1: > > /usr/include/g++/backward/backward_warning.h:32:2: > > warning: #warning This file includes at least one > > deprecated or antiquated header. Please consider > using > > one of the 32 headers found in section 17.4.1.2 of > the > > C++ standard. Examples include substituting the > <X> > > header for the <X.h> header for C++ includes, or > > <sstream> instead of the deprecated header > > <strstream.h>. To disable this warning use > > -Wno-deprecated. > > liss.cpp: In member function `void > menu::tampil()': > > liss.cpp:19: error: `samba' undeclared (first use > this > > function) > > liss.cpp:19: error: (Each undeclared identifier is > > reported only once for each > > function it appears in.) > > liss.cpp:19: error: `s' undeclared (first use this > > function) > > liss.cpp:19: error: syntax error before `(' token > > liss.cpp: At global scope: > > liss.cpp:39: error: `struct samba' used prior to > > declaration > > patrixlinux@patrix:~/arsip/proyek/gcc/liss> > > ==== > > > > Why is it so? > > > > Thank you very much in advance. > > > > ps.Sorry for my stupid question. > > ==== > > Here is my code. > > ==== > > #include <iostream.h> > > #include <ctype.h> > > #include <stdlib.h> > > > > class menu { > > public: > > char pilihan; > > void tampil(); > > > > }; > > > > void menu::tampil(){ > > for (;;){ > > cout << "Menu : (S)amba (P)ostfix (B)ind > (Q)uit\n"; > > cin >> pilihan; > > switch ( toupper(pilihan) ){ > > case 'S': > > cout << "You are administrating Samba Server" << > endl; > > samba * s = new samba(); > > s->tampil(); > > > > break; > > case 'P': > > cout << "You are administrating Postfix Server" << > > endl; > > break; > > case 'B': > > cout << "You are administrating BIND Server" << > endl; > > break; > > case 'Q': > > cout << "You selected Quit. Good bye!" << endl; > > exit(0); > > default: > > cout << "***No such command!***" << endl; > > break; > > } > > } > > } > > > > class samba { > > public: > > char resource[50]; > > void tampil(); > > }; > > > > void samba::tampil(){ > > for(;;){ > > cout << "Share file or directory: "; > > cin >> resource; > > } > > } > > > > int main(){ > > menu * m = new menu(); > > m->tampil(); > > return 0; > > } > > > > __________________________________ > > Do you Yahoo!? > > Yahoo! Mail - 50x more storage than other > providers! > > http://promotions.yahoo.com/new_mail > > > > -- > > To unsubscribe, email: > suse-programming-e-unsubscribe(a)suse.com > > For additional commands, email: > suse-programming-e-help(a)suse.com > > Archives can be found at: > http://lists.suse.com/archive/suse-programming-e > > > > > _______________________________ Do you Yahoo!? Declare Yourself - Register online to vote today! http://vote.yahoo.com

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GNU C++ (beginner question)
by Prabu Subroto 03 Oct '04

03 Oct '04

Dear my friends... I am trying to learn and practice GNU C++. I start with this very simple program: ===== #include <iostream.h> #include <ctype.h> #include <stdlib.h> class menu { public: int pilihan; void tampil(); }; int main(){ menu * m = new menu(); m->tampil(); return 0; } void menu::tampil(){ for (;;){ cout << "Menu : (S)amba (P)ostfix (B)ind (Q)uit\n"; cin >> pilihan; switch ( toupper(pilihan) ){ case 'S': cout << "You are administrating Samba Server" << endl; break; case 'P': cout << "You are administrating Postfix Server" << endl; break; case 'B': cout << "You are administrating BIND Server" << endl; break; cout << "You selected Quit. Good bye!" << endl; case 'Q': exit(0); default: cout << "***No such command!***" << endl; break; } } } ===== I compiled it successfully, as below : ===== patrixlinux@patrix:~/arsip/proyek/gcc/1> ls liss liss.cpp liss.cpp~ patrixlinux@patrix:~/arsip/proyek/gcc/1> g++ -o liss liss.cpp In file included from /usr/include/g++/backward/iostream.h:31, from liss.cpp:1: /usr/include/g++/backward/backward_warning.h:32:2: warning: #warning This file includes at least one deprecated or antiquated header. Please consider using one of the 32 headers found in section 17.4.1.2 of the C++ standard. Examples include substituting the <X> header for the <X.h> header for C++ includes, or <sstream> instead of the deprecated header <strstream.h>. To disable this warning use -Wno-deprecated. patrixlinux@patrix:~/arsip/proyek/gcc/1> ./liss Menu : (S)amba (P)ostfix (B)ind (Q)uit s ==== But the problem is my program does not run as expected. It does like this below without ending: ==== Menu : (S)amba (P)ostfix (B)ind (Q)uit ***No such command!*** Menu : (S)amba (P)ostfix (B)ind (Q)uit ***No such command!*** Menu : (S)amba (P)ostfix (B)ind (Q)uit ***No such command!*** Menu : (S)amba (P)ostfix (B)ind (Q)uit ***No such command!*** Menu : (S)amba (P)ostfix (B)ind (Q)uit ***No such command!*** Menu : (S)amba (P)ostfix (B)ind (Q)uit ***No such command!*** ==== I aborted with <control>-<C>. what's wrong with my code? Lookslike my code does not receive the pressed key properly. Please help. Thank you very much in advance. __________________________________ Do you Yahoo!? Yahoo! Mail - 50x more storage than other providers! http://promotions.yahoo.com/new_mail

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tar runs fine from a command line but not in script?
by Patrick B. O'Brien 30 Sep '04

30 Sep '04

Running the following from a command line, it works, the *.gz is created. From within a script, the *.gz file is created but its 0 bytes? Any help out there today? TIA. /bin/tar -cvf- /etc | /bin/gzip -9 > /humboldt/osbackup/`hostname`.etc.gz

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Registering another class as a variable in one class (Beginner Question).
by Prabu Subroto 30 Sep '04

30 Sep '04

Dear my friends.. I am practicing GNU C++ on SuSE 9.1. But if I compile my code I got this error message as below: ==== patrixlinux@patrix:~/arsip/proyek/gcc/liss> g++ -o liss ./liss.cpp In file included from /usr/include/g++/backward/iostream.h:31, from liss.cpp:1: /usr/include/g++/backward/backward_warning.h:32:2: warning: #warning This file includes at least one deprecated or antiquated header. Please consider using one of the 32 headers found in section 17.4.1.2 of the C++ standard. Examples include substituting the <X> header for the <X.h> header for C++ includes, or <sstream> instead of the deprecated header <strstream.h>. To disable this warning use -Wno-deprecated. liss.cpp: In member function `void menu::tampil()': liss.cpp:19: error: `samba' undeclared (first use this function) liss.cpp:19: error: (Each undeclared identifier is reported only once for each function it appears in.) liss.cpp:19: error: `s' undeclared (first use this function) liss.cpp:19: error: syntax error before `(' token liss.cpp: At global scope: liss.cpp:39: error: `struct samba' used prior to declaration patrixlinux@patrix:~/arsip/proyek/gcc/liss> ==== Why is it so? Thank you very much in advance. ps.Sorry for my stupid question. ==== Here is my code. ==== #include <iostream.h> #include <ctype.h> #include <stdlib.h> class menu { public: char pilihan; void tampil(); }; void menu::tampil(){ for (;;){ cout << "Menu : (S)amba (P)ostfix (B)ind (Q)uit\n"; cin >> pilihan; switch ( toupper(pilihan) ){ case 'S': cout << "You are administrating Samba Server" << endl; samba * s = new samba(); s->tampil(); break; case 'P': cout << "You are administrating Postfix Server" << endl; break; case 'B': cout << "You are administrating BIND Server" << endl; break; case 'Q': cout << "You selected Quit. Good bye!" << endl; exit(0); default: cout << "***No such command!***" << endl; break; } } } class samba { public: char resource[50]; void tampil(); }; void samba::tampil(){ for(;;){ cout << "Share file or directory: "; cin >> resource; } } int main(){ menu * m = new menu(); m->tampil(); return 0; } __________________________________ Do you Yahoo!? Yahoo! Mail - 50x more storage than other providers! http://promotions.yahoo.com/new_mail

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RE: [suse-programming-e] separating files based on its extension
by Hallingstad Håkon 30 Sep '04

30 Sep '04

The below should not fail when directories/files contains spaces, it ignores non-regular files and non-standard filenames (like .hello). As input arguments, it takes any number of files and directories (directories are expanded to its containing files). Run the script without arguments to view a description of what it does. I hope the format of the below bash script does not get messed up on the way to your inboxes, as usually happens with the mailinglist's emails to my inbox. ------start #! /bin/bash # Exit on unexpected error set -e # Set how '*' should expand shopt -s dotglob nullglob if [ "$1" == "-v" ] then VERBOSE=1 shift fi if (($#<1)) then cat <<EOF >&2 Usage: $0 [-v] FILE... Moves each FILE to a subdirectory whose name is FILE's extension -v Does not change any files/directories, but shows the commands that would have been executed. $0 operates on each input argument independently. If an argument is a directory, it is expanded to the files of that directory. Only regular file are operated on. A file is generally of the form DIRECTORY/PREFIX.EXTENSION, where EXTENSION does not contain any '.'. First the directory DIRECTORY/EXTENSION is made, and then the file is moved to DIRECTORY/EXTENSION/PREFIX.EXTENSION. EOF #' This comment is for the font-lock-mode in xemacs exit 1 fi # Precondition: Receives one argument that must be a path to an # existing regular file transform() { path="$1" filename="${path##*/}" directory="${path%$filename}" prefix="${filename%.*}" ext="${filename#$prefix}" if [ -z "$prefix" ] then echo "$path: Filename prefix is empty" >&2 return elif [ -z "$ext" -o "$ext" == "." ] then echo "$path: Extension is empty" >&2 return fi ext="${ext#.}" newdir="$directory$ext" if [ -z "$VERBOSE" ] then mkdir -p "$newdir" mv "$path" "$newdir/$filename" else echo "mkdir -p \"$newdir\"" echo "mv \"$path\" \"$newdir/$filename\"" fi return } for FILE in "$@" do if [ -f "$FILE" ] then transform "$FILE" elif [ -d "$FILE" ] then for file in "$FILE"/* do if [ -f "$file" ] then transform "$file" fi done fi Done ------end Håkon Hallingstad -----Original Message----- From: hart [mailto:ody@inf.its-sby.edu] Sent: 30. september 2004 00:43 To: suse-programming-e(a)suse.com Subject: [suse-programming-e] separating files based on its extension I am a bash newbie, having difficulties making some script. I have some directories containing filez with many extension. I want to separate those filez into new directory on the filez' directory and name the new dir as the filez' extesion. I wonder to know how the bash script look like? For example, /foo/a.pdf moved to /foo/pdf/a.pdf /foo/a.s.zip moved to /foo/zip/a.s.zip /foo/a.b.123 moved to /foo/123/a.b.123 ad so on Thx in advance. -- --- hart -- To unsubscribe, email: suse-programming-e-unsubscribe(a)suse.com For additional commands, email: suse-programming-e-help(a)suse.com Archives can be found at: http://lists.suse.com/archive/suse-programming-e

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RE: [suse-programming-e] separating files based on its extension
by Wenzel, Scott 30 Sep '04

30 Sep '04

Very well put! After helping someone overcome a difficult algorithm is nice but it is nicer when they respond with a simple 'Thank you'... Did I miss a posting to Jan or Daryl? -----Original Message----- From: Stefan Hundhammer [mailto:sh@suse.de] Sent: Wednesday, September 29, 2004 1:29 PM To: suse-programming-e(a)suse.com Subject: Re: [suse-programming-e] separating files based on its extension On Wednesday 29 September 2004 18:36, Daryl Lee wrote: > This dialog raises an intersting question: when should people start > learning how to seek help? They should learn that soon, but they should also realize that they cannot reasonably expect others to do their work. Bothering others with one's problems is justifiable after having done everything that can reasonably be expected to solve the problem of one's own - such as RTFM (I know, nobody bothers about that any more today) and trying some different approaches. > In Jerry Harvey's book "The Abilene Paradox" > he tells of teaching a class where the refusal to cheat was sufficient > cause to flunk the course. "Cheating" was defined as asking for or > giving help on an exam or homework assignment. His intent was to teach > his students that they perform better as a team than as a collection of > isolated individuals. I consider that a very strange attitude. Asking others is OK if you are stuck, but that is no excuse for giving up at the first sight of a problem. > If Mr. Ody (skipping the gender question for now) learns something as a > result of this, then I believe we're all the better for it. If he > simply turns my work in as his own, without learning a few Bash > concepts, it will catch up to him soon enough. I doubt that. I know several people studying computer science with me who essentially got their degrees for other people's work - being part of teams full of enthusiasts yet not doing a damn to contribute. After receiving their degrees, they typically seeked jobs as consultants - the talk-heavy side, not doing very much technical stuff. Did that backfire on them? Not that I know of. They simply benefited from others being social enough (or call it stupid) to drag them through the courses. Just my $0.02 -- Stefan Hundhammer <sh(a)suse.de> Penguin by conviction. YaST2 Development SuSE Linux AG Nuernberg, Germany -- To unsubscribe, email: suse-programming-e-unsubscribe(a)suse.com For additional commands, email: suse-programming-e-help(a)suse.com Archives can be found at: http://lists.suse.com/archive/suse-programming-e

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separating files based on its extension
by hart 29 Sep '04

29 Sep '04

I am a bash newbie, having difficulties making some script. I have some directories containing filez with many extension. I want to separate those filez into new directory on the filez' directory and name the new dir as the filez' extesion. I wonder to know how the bash script look like? For example, /foo/a.pdf moved to /foo/pdf/a.pdf /foo/a.s.zip moved to /foo/zip/a.s.zip /foo/a.b.123 moved to /foo/123/a.b.123 ad so on Thx in advance. -- --- hart

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older java and SuSe 9.1
by MC 29 Sep '04

29 Sep '04

Hi, have somebody success with running java version<1.3? There is problem with version glibc :-( I have an old project what is already long time running by customer, but sometimes need to change something. Thank You. M@ra mkonfery(a)seznam.cz

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Where's reparent_to_init in 2.6??
by Timothy Moulton 29 Sep '04

29 Sep '04

Does anybody know what the history is with the absence of the function reparent_to_init() in the 2.6 kernel? SLES 9.0 has it as an exported symbol but Suse 9.1 doesn't. Which is the wave of the future? Is the daemonize function supposed to be what is used instead? Any info, links or workarounds would be great. Thanks. Tim

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RE: [suse-programming-e] separating files based on its extension
by Wenzel, Scott 29 Sep '04

29 Sep '04

Must be a school assignment.. Second request from the same domain... No help from me if it is.... -----Original Message----- From: hart [mailto:ody@inf.its-sby.edu] Sent: Wednesday, September 29, 2004 6:43 PM To: suse-programming-e(a)suse.com Subject: [suse-programming-e] separating files based on its extension I am a bash newbie, having difficulties making some script. I have some directories containing filez with many extension. I want to separate those filez into new directory on the filez' directory and name the new dir as the filez' extesion. I wonder to know how the bash script look like? For example, /foo/a.pdf moved to /foo/pdf/a.pdf /foo/a.s.zip moved to /foo/zip/a.s.zip /foo/a.b.123 moved to /foo/123/a.b.123 ad so on Thx in advance. -- --- hart -- To unsubscribe, email: suse-programming-e-unsubscribe(a)suse.com For additional commands, email: suse-programming-e-help(a)suse.com Archives can be found at: http://lists.suse.com/archive/suse-programming-e

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