On 2015-06-17 13:51, James Knott wrote:
On 06/17/2015 02:09 AM, Hans de Faber wrote:
Not correct 0,5I x 0,5U = 0.25 power it takes 4 times longer to heat.
If you're making the calculation I thing you are (What is U? Do you mean V?), then it is indeed 1/2, as time is now a factor. By using the diode, you're cutting the duty cycle in half (approximately). You're also generating significant noise on the line.
Yes, it is half duty cycle. Power is half, I measured it. There is noise, yes, but it does not seem to have adverse effects, and I need it (halving the power). I have seen the same trick on commercially sold devices, so I went ahead. If you want to continue the discussion on offtopic mail list, I'll be happy to do so, but tell me first so that I have time to subscribe. I'm not there at present, and there is no archive. -- Cheers / Saludos, Carlos E. R. (from 13.1 x86_64 "Bottle" at Telcontar)