https://bugzilla.novell.com/show_bug.cgi?id=794505
https://bugzilla.novell.com/show_bug.cgi?id=794505#c7
--- Comment #7 from Peter Benie 2012-12-15 14:07:42 GMT ---
I can 'fix' the installer for this particular machine by doing:
sfdisk -d /dev/sda | sfdisk -H 47 -S 36 /dev/sda; hdparm -z /dev/sda
and I can break it again by doing:
sfdisk -d /dev/sda | sfdisk -H 255 -S 63 /dev/sda; hdparm -z /dev/sda
The MBR attachment has the partitions in the broken state, ie.
a H S C t H S C | start LBA end LBA
01BE: 80 09 21 01 07 2e e4 ff | 00 08 00 00 00 80 6d 0d
I noticed that fdisk did not consider the space below sector 2048 as available
even when H=47 and S=36. I had a look at the logic inside. It seems that fdisk,
when not running in DOS compatibility mode (the default is not to), aims to
have alignment on 1M boundaries - 2048*512bytes, in order to match Windows
Vista
fdisk may deviate from this policy if the disk is special (eg. RAID) or if the
disk has stricter alignment properties, or if the disk is particularly small
(<4MB).
I wonder if it would be sensible to use the same policy as fdisk in the
autoinstaller?
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