http://bugzilla.opensuse.org/show_bug.cgi?id=1048783
http://bugzilla.opensuse.org/show_bug.cgi?id=1048783#c3
--- Comment #3 from Richard Weinberger ---
Meh, fixed upstream a long time ago, please backport.
commit 69722fd7ac854f95eac65a4bf3fd86e65fbc470f
Author: Stefan Bader
Date: Fri Oct 7 09:56:32 2016 +0200
tools: Ignore newlines in libvirt-guests.sh guest list
The list file expects all guest UUIDs on the same line as the URI
which the guests run on. This does not happen when the list is
echo'ed in quotes. When stripping the quotes, newlines get transformed
into spaces. Without this, only the first guest on the list is actually
handled.
Based on a fix by Omar Siam
Bug-Ubuntu: http://bugs.launchpad.net/bugs/1591695
Signed-off-by: Stefan Bader
diff --git a/tools/libvirt-guests.sh.in b/tools/libvirt-guests.sh.in
index 7f74b85c19d7..7380b4b809b7 100644
--- a/tools/libvirt-guests.sh.in
+++ b/tools/libvirt-guests.sh.in
@@ -499,7 +499,7 @@ stop() {
fi
if [ -n "$list" ]; then
- echo "$uri" "$list" >>"$LISTFILE"
+ echo "$uri" $list >>"$LISTFILE"
fi
done
set +f
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