Can someone explain the following firewall trace? I run a Linux box (not in LAN) that is connected to the Internet via PPP. Look at the IP addresses: 195.130.232.21 is not mine! Whose are they? And what kind of address is the 224.0.0.1 (reserved!)? Thank you in advance. Feb 18 16:05:34 myhost kernel: SuSE-FW-ILLEGAL-TARGET IN=ppp0 OUT= MAC= SRC=195.130.232.21 DST=224.0.0.1 LEN=32 TOS=0x00 PREC=0xC0 TTL=1 ID=56123 OP (94040000) PROTO=2 Feb 18 16:06:35 myhost kernel: SuSE-FW-ILLEGAL-TARGET IN=ppp0 OUT= MAC= SRC=195.130.232.21 DST=224.0.0.1 LEN=32 TOS=0x00 PREC=0xC0 TTL=1 ID=58787 OP (94040000) PROTO=2 Feb 18 16:07:35 myhost kernel: SuSE-FW-ILLEGAL-TARGET IN=ppp0 OUT= MAC= SRC=195.130.232.21 DST=224.0.0.1 LEN=32 TOS=0x00 PREC=0xC0 TTL=1 ID=61542 OP (94040000) PROTO=2 Feb 18 16:08:35 myhost kernel: SuSE-FW-ILLEGAL-TARGET IN=ppp0 OUT= MAC= SRC=195.130.232.21 DST=224.0.0.1 LEN=32 TOS=0x00 PREC=0xC0 TTL=1 ID=64584 OP (94040000) PROTO=2 Feb 18 16:09:37 myhost kernel: SuSE-FW-ILLEGAL-TARGET IN=ppp0 OUT= MAC= SRC=195.130.232.21 DST=224.0.0.1 LEN=32 TOS=0x00 PREC=0xC0 TTL=1 ID=1934 OPT (94040000) PROTO=2 Feb 18 16:10:37 myhost kernel: SuSE-FW-ILLEGAL-TARGET IN=ppp0 OUT= MAC= SRC=195.130.232.21 DST=224.0.0.1 LEN=32 TOS=0x00 PREC=0xC0 TTL=1 ID=4839 OPT (94040000) PROTO=2 Feb 18 16:10:50 myhost kernel: SuSE-FW-DROP-DEFAULT IN=ppp0 OUT= MAC= SRC=62.135.1.27 DST=62.11.78.46 LEN=78 TOS=0x00 PREC=0x00 TTL=105 ID=2133 PROTO=UDP SPT=1026 DPT=137 LEN=58 Feb 18 16:11:37 myhost kernel: SuSE-FW-ILLEGAL-TARGET IN=ppp0 OUT= MAC= SRC=195.130.232.21 DST=224.0.0.1 LEN=32 TOS=0x00 PREC=0xC0 TTL=1 ID=7692 OPT (94040000) PROTO=2