At 12:52 21/08/01 -0700 you scribbled:
Hi Laurence,
You are missing one crucial point, and that is you are ignoring the impedance(Resistance) of the actual processor involved!
Are you saying then that the impedance of the processor involved changes?
v = electrical potential(voltage) i = current r = resistance p = power
v = i * r p = v * i
or with substitution, p = i^2 * r
Now, if you believe that with higher voltage, you will get higher power, then you should also believe the next few lines:
I am not saying that with higher voltage you get higher power, I am saying that with higher voltage you get lower current at the same power.
Case 1 Voltage = V1 Power used = 30w resistance(constant) = R2
Case 2 Voltage = V2 higher than V1 Power used = 35w resistance(constant) = R2
using p = i^2 * r, you should find that the second current is higher than the first. Current cant and wont stay constant. If you have a different proof, I would like to see it.
Are you saying that as the processing load increases, the power (wattage) increases or that the impedance (resistance) increases? If you are saying that
Sinan
--- Laurence Orchard
wrote: At 11:39 20/08/01 +0300 you scribbled:
Hi
Correct... And even more so, because the fact that with higher core voltage the rise/fall times decreases, and thus consumes more power, generates more heat, and generate more RF- and EMI
Jaska.
Don't understand about the rise/fall times decreasing?
Using the standard formula watts = volts * amps if the required power remains the same then if you increase the voltage the current must fall!
if the power requirement does increase then with a higher voltage the current will not rise as high.
2 watts = 1volt * 2amps or 2 watts = 2volts * 1amp
therefore
4watts = 1volt * 4amps or 4watts = 2volts * 2amps
Laurence Orchard wrote:
At 09:25 16/08/01 -0700 you scribbled:
Hello Guy,
<snip>
Remember that increasing the core voltage to you CPU would increase the produced heat. Though, I don't think its the temperature that is causing your problem. Try e-mailing AMD and asking them if increasing the voltage to you cpu wouldn't in any way void your warranty since you would be running you CPU out of spec and that is not recommended.
Increasing the core voltage does not increase
Viestiss Maanantai 20. Elokuuta 2001 11:39, Mark Hounschell kirjoitti: the amount of heat produced
it should reduce it, more volts = less amps = less current = less heat
more volts with same impeddance = more amps
1volt into 1 ohm = 1amp 2volt into 1 ohm = 2amp 2volt into 2 ohm = 1amp
Laurence
** if you want to know what the program really does, look at the code **
laurence@orchards.org.uk
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