Hello Mates, i have a short Question about chmod. I've a tar.bz2. Inside that folder, i can find the binary under program/ Now i tried the following to make it executable: %install # install binary find %{buildroot} -name %{name} -type f -print0 | xargs -0 chmod 755 %__install -d ${RPM_BUILD_ROOT}%{_bindir} %__install program/%{name} ${RPM_BUILD_ROOT}%{_bindir} But the find function breaks with: Executing(%install): /bin/sh -e /var/tmp/rpm-tmp.OLvIbg + umask 022 + cd /usr/src/packages/BUILD + cd whohas-0.24 + find /usr/src/packages/BUILDROOT/whohas-0.24-0.x86_64 -name whohas - type f -print0 + xargs -0 chmod 755 chmod: missing operand after `755' Have i forgotten anything? -- Sincerely yours Sascha Manns open-slx GmbH openSUSE Community & Support Agent openSUSE Marketing Team Blog: http://saigkill.wordpress.com Web: http://www.saschamanns.de Web: http://www.open-slx.de (openSUSE Box Support German) Web: http://www.open-slx.com (openSUSE Box Support English) Open-SLX : Linux convenient, simple, secure and complete