When creating a software RAID volume using IDE devices the advice is to put just one disk per channel. According the the Software RAID FAQ... "It is very important, that you only use one IDE disk per IDE bus. Not only would two disks ruin the performance, but the failure of a disk often guarantees the failure of the bus, and therefore the failure of all disks on that bus." For my purpose I'm not interested in fault-tolerance but speed. The performance problem is due to trying to access two devices at the same time on the same channel. So why not make a linear disk out of the two devices on the each channel and then stripe across the two linear disks. This should effectively double disk performance. But is it possible with LVM? ______disk0 Ch.A ----<______ disk1 ______disk2 Ch.B ----<______ disk3 lvm_a = linear disk0 + disk1 lvm_b = linear disk2 + disk3 lvm_z = stripe lvm_a + lvm_b Is this possible? Is there a flaw in my proposal? P.s. I know there are hardware solutions to this problem. -- Simon Oliver