On Wednesday 19 September 2001 15:49, Linux - User wrote:

Hi guys...

is there any way to make with the Shell a for or any other loop statement to make a loop like this:

01 02 03 .... 10 11 12..

That's because I need the zero before the number when the number is below 10.

thanks

bye

--ed

Ed, Perhaps something like this? It should give you some ideas, at least. N=1 until [ $N -eq 13 ]; do if [ $N -lt 10 ]; then echo 0$N else echo $N fi let N+=1 done Kevin -- Sleep is perhaps the only of life's great pleasures that need not be of short duration.

01 02 03 ... 10 11 12..

That's because I need the zero before the number when the number is below 10.

Oh dear... (after looking at previous proposals) This is SOO simple: printf %02d $cnt (You may use `printf %4d $cnt` to make the decimal representation of cnt (at least) 4 characters long; printf is a builtin shell command.) Example: declare -i cnt=0 # declare integer counter <loop begin statement> string="`printf %02d $cnt`" # string= "00","01","02"..."09","10","11"... cnt=$cnt+1 # increment integer counter <loop end statement> Wolly -- Some operating systems are called "user friendly". Linux, however, is "expert friendly".