Is there some where that I can get this information? I thank you for your help, I even understand some of it ;). ----- Original Message ----- From: Stefan Troeger <stefan.troeger@wirtschaft.tu-chemnitz.de> To: suse-linux-e <suse-linux-e@suse.com> Sent: Monday, December 27, 1999 6:35 PM Subject: Re: [SLE] Shell Programing
Hi,
On Mon, Dec 27, 1999 at 15:30 -0600, khadji@pld.com wrote:
I have a directory, say c:\top, that has sub directories c:\top\001, c:\top\002, etc. I want to run a script from c:\top (mounted as /smb on Linbox) that will go through the subdirectories renaming each file starting with 000001. I have the script written except that it starts with 1 and goes up. I also need the files to retain their extensions so I had forseen something to read the file name, slice the ext off and then reattach it, ie. abcdef.txt=>000001.txt. I am attaching what I have so far. I am making this up as I go with one eye on 'Beginning Linux Programing' from Wrox Press. Thanks for the help. [...] #! /bin/bash
x=000001
for directories in * do if -d $directories
This should be
if [ -d "$directories" ]
then for files in $directories/* do if -f $files
if [ -f "$files" ]
then mv $files $x
Enclose the variable names in double quotes. Otherwise your script will fail on filenames with spaces:
[sttr]/var/tmp/1> touch "a b" [sttr]/var/tmp/1> ls a b [sttr]/var/tmp/1> for x in *; do mv $x foo; done mv: when moving multiple files, last argument must be a directory [sttr]/var/tmp/1> ls a b [sttr]/var/tmp/1> for x in *; do mv "$x" foo; done [sttr]/var/tmp/1> ls foo
x=$(($x+1)) fi done fi done
Hmm. One problem with your script is that it won't descend into all subdirectories. If you had a directory c:\top\001\001, it would never be visited. To remedy this I'd use find to create a list of all files in the current directory and its subdirectories.
#!/bin/sh i=1 for x in $(find . -type f); do mv "$x" "$(dirname $x)/$(printf "%06d" $i)$(echo $x |sed 's#.*\(\.\)#\1#g')" i=$((i+1)) done
should do it. The mv line may look a little tricky but it really isn't. Suppose $x contained ./top/001/abcdef.txt and $i was 5. Then
dirname $x
would give you the directory name ./top/001.
printf "%06d" $i
would output 000005.
echo $x |sed 's#.*\(\.\)#\1#g'
gives you the extenstion .txt. Finally everything is concatenated to
./top/001/000005.txt
Ciao, Stefan
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