Hi, as I understand it, you have it as you want already (almost). /dev/hda is the whole disk (from cylinder 0 to 7294, 55.8 GB, not only MBR) hda1 and 2 are the two primary partition. In the first one you have NT, the second is entirely used by one "extended" partition (hdax with x>= 5), currently of type FAT16, where you want to install Linux. The thing is, HD can only have 4 primary partitions, so nowadays (I saw this before), OS installation procedures suggest you to go directly for an primary partition of type "extended", where you can put as many secondary as you want. Even if in this case is just one... I hope someone is able to explain it better than this, but I think you are set already. Davide On 8/19/05, Buddy Lindsey <percent20@gmail.com> wrote:
Ok, I am trying to partition my HD but I don't understand what is going on here. With 9.3 It was easy to understand, but now I am confused it says
device size type start end /dev/hda 55.8 hts58060m91t00 0 7294 /dev/hda1 43.8 HPFS/NTFS 0 5728 /dev/hda2 11.9 Extended 5729 7294 /dev/hda5 11.9 Win95 FAT16 5729 7294
I thought that /dev/hda was the MBR so I don't see how it is 55.8 gb. Now i can understand why /dev/hda1 is 43.8 gig because I set it that big.
THe most confusing point is the extended and the win95 partitions are both set to 11.9gig and i cant seem to removee either to change it. Does anyone have any suggestions? I need to dual boot this system, but don't want to resize it. I need the 11.9 gig to be the suse partition. I also can't remove the windows partition at all. Any ideas and help would be appreicated.
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