Отправлено с iPhone
19 авг. 2019 г., в 11:26, "jdd@dodin.org" <jdd@dodin.org> написал(а):
Le 18/08/2019 à 19:20, jdd@dodin.org a écrit :
Le 18/08/2019 à 12:08, jdd@dodin.org a écrit :
Le 18/08/2019 à 09:28, jdd@dodin.org a écrit :
may I use
btrfs balance start -mconvert=dup -dconvert=single / btrfs device remove /dev/sdb2 /
but no. I could work without problem, but not boot... more on that later :-(
it may be -or not- a file system problem if not see an other post :-)
I was thinking that when separating two raid1 mirror disks (partitions, in fact), I would have two identical partitions as a result.
obviously it was not
in the command listed above, I kept the /dev/sda2 one and this one is not bootable (see other post), but readable.
But the /dev/sdb2 removed is no more a true btrfs bootable file system. I can't even mount it.
Is this normal? if so I will try an other thing (that is rebuild the btrfs raid1 and remove the other partition, that is sda2)
So my question is: is it normal than the removed partition be unusable?
Yes. “btrfs device remove” by design clears metadata on device that is being removed so it is no more part of btrfs. I am not aware of any graceful btrfs split. True splitting would involve at least changing UUID for all subvolumes. And those are interrelated (think about parent or received UUID). I do not know if this is possible at all. -- To unsubscribe, e-mail: opensuse+unsubscribe@opensuse.org To contact the owner, e-mail: opensuse+owner@opensuse.org