Re: [suse-programming-e] reading a file and display its content with cout

31 Jan 2005


      On Monday 31 January 2005 10:00, Prabu Subroto wrote:
...
do you mean like this:
"
char mybuffer[];
fstream sumber("smb.conf");
if (!sumber){
    cout << "Failed in opening the 'smb.conf'
    file\n";
    exit(1);
    }
sumber >> mybuffer;
cout << mybuffer << endl;
"?
Please tell me more details. Could you give me a very
simple sample?
yes, but you are not allocating space for mybuffer. You must declare a size.
In the case below, I create a file, test.dat, but you could use smb.conf
Nore that the >> operator reads a word. If you want to read a line, use the 
getline() member function. Here is an example, below.
#include <iostream>  
#include <fstream>
using std::cin;
using std::cout;
using std::cerr;
using std::fstream;
using std::endl;
using std::ios;
main ()
{
fstream file1;
  
  char mybuffer[512]; 
  file1.open( "/etc/samba/smb.conf", ios::in); 
  if (!file1) 
    {
      cerr << "Unable to open test.dat." << endl;
      exit(1);
    }
  while( !file1.eof() ) {
    file1.getline(mybuffer, sizeof(mybuffer));
    cout << mybuffer << endl;
  }
  file1.close();  
}

-- 
Jerry Feldman <gaf@blu.org>
Boston Linux and Unix user group
http://www.blu.org PGP key id:C5061EA9
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