http://bugzilla.suse.com/show_bug.cgi?id=967968 http://bugzilla.suse.com/show_bug.cgi?id=967968#c3 Dr. Werner Fink changed: What |Removed |Added ---------------------------------------------------------------------------- CC| |rguenther@suse.com Flags| |needinfo?(schwab@suse.com) --- Comment #3 from Dr. Werner Fink --- (In reply to Andreas Schwab from comment #2)

6 is SIGABRT, of course, and 0x79fc9 is inside free(3). Classical memory corruption.

OK ... how do you determine the value 0x79fc9 ... AFAICS from kernel: [295139.801642] systemd[1]: segfault at 55c1198268b8 ip 00007fde212befc9 sp 00007ffe343fa380 error 6 in libc-2.22.so[7fde21244000+19c000]" and with the help of the gnome-calculator I do `ip - libc map address' 0x00007fde212befc9−0x7fde21244000 = 0x7afc9 also gdb shows me (gdb) print /x 0x00007fde212befc9-0x7fde21244000 $1 = 0x7afc9 (gdb) info symbol 0x00007fde212befc9 _int_malloc + 409 in section .text of /lib64/libc.so.6 (gdb) info symbol 0x7fde21244000+0x7afc9 _int_malloc + 409 in section .text of /lib64/libc.so.6 indeed 0x79fc9 is (gdb) info symbol 0x7fde21244000+0x79fc9 _int_free + 2169 in section .text of /lib64/libc.so.6 but how you estimate the value 0x79fc9? -- You are receiving this mail because: You are on the CC list for the bug.