https://bugzilla.novell.com/show_bug.cgi?id=209361 f-perret@tiscali.fr changed: What |Removed |Added ---------------------------------------------------------------------------- Status|NEEDINFO |ASSIGNED Info Provider|f-perret@tiscali.fr | ------- Comment #2 from f-perret@tiscali.fr 2006-10-01 08:09 MST ------- Can't find any bug in bugzilla.kernel.org about this, so I don't think it had been include in 2.6.19 git. I've post a new bug : http://bugzilla.kernel.org/show_bug.cgi?id=7243 For the moment (and for the time it will be include), I can't compile this driver. When I done : "make clean modules" I obtain (I'm running SLED 10 with kernel 2.6.16.21) : make -C src/ clean make[1]: Entering directory `/windows/D/Progs/Linux/Asus/r1000_v1.04/src' rm -f *.o *.ko *~ core* .dep* .*.d .*.cmd *.mod.c *.a *.s .*.flags make[1]: Leaving directory `/windows/D/Progs/Linux/Asus/r1000_v1.04/src' make -C src/ modules make[1]: Entering directory `/windows/D/Progs/Linux/Asus/r1000_v1.04/src' make -C /lib/modules/2.6.16.21-0.15-smp/build SUBDIRS=/windows/D/Progs/Linux/Asus/r1000_v1.04/src modules make[2]: Entering directory `/usr/src/linux-2.6.16.21-0.15-obj/i386/smp' make -C ../../../linux-2.6.16.21-0.15 O=../linux-2.6.16.21-0.15-obj/i386/smp modules /windows/D/Progs/Linux/Asus/r1000_v1.04/src/Makefile:28: /usr/src/linux-2.6.16.21-0.15/src/Makefile_linux26x: Aucun fichier ou répertoire de ce type make[5]: *** Pas de règle pour fabriquer la cible « /usr/src/linux-2.6.16.21-0.15/src/Makefile_linux26x ». Arrêt. make[4]: *** [_module_/windows/D/Progs/Linux/Asus/r1000_v1.04/src] Erreur 2 make[3]: *** [modules] Erreur 2 make[2]: *** [modules] Erreur 2 make[2]: Leaving directory `/usr/src/linux-2.6.16.21-0.15-obj/i386/smp' make[1]: *** [modules] Erreur 2 make[1]: Leaving directory `/windows/D/Progs/Linux/Asus/r1000_v1.04/src' make: *** [modules] Erreur 2 -- Configure bugmail: https://bugzilla.novell.com/userprefs.cgi?tab=email ------- You are receiving this mail because: ------- You are on the CC list for the bug, or are watching someone who is.