Guys, How do I call 'ls' from within a script without it also returning the contents of the present working directory? Here is the line from my script: ls -al /usr/lib/libGL.so* Here is the output: # ./linux/scripts/showLibConfig 250sata.pdf 7857.pdf Bannykh-ArizMedBoard.pdf Bannykh-TennMedBoard.pdf bin broadway.pdf david.asc Desktop Documents linux log Pictures public_html westlaw-renewal_20071129.pdf /usr/lib/libGL.so Config lrwxrwxrwx 1 root root 10 2007-11-09 16:19 /usr/lib/libGL.so -> libGL.so.1 lrwxrwxrwx 1 root root 12 2007-12-16 16:25 /usr/lib/libGL.so.1 -> libGL.so.1.2 lrwxrwxrwx 1 root root 27 2007-12-16 16:25 /usr/lib/libGL.so.1.2 -> /usr/X11R6/lib/libGL.so.1.2 -rwxr-xr-x 1 root root 391344 2007-09-21 20:34 /usr/lib/libGL.so.1.2.sav as you can see, it looks like 'ls' is evaluated before 'ls -al /usr/lib/libGL.so*' gets evaluated. How do I fix this? -- David C. Rankin, J.D., P.E. Rankin Law Firm, PLLC 510 Ochiltree Street Nacogdoches, Texas 75961 Telephone: (936) 715-9333 Facsimile: (936) 715-9339 www.rankinlawfirm.com -- To unsubscribe, e-mail: opensuse+unsubscribe@opensuse.org For additional commands, e-mail: opensuse+help@opensuse.org