https://bugzilla.novell.com/show_bug.cgi?id=340722 Summary: Can be impossible to dual-boot Windows Vista and openSUSE 10.3 with default grub config Product: openSUSE 10.3 Version: Final Platform: x86-64 OS/Version: Other Status: NEW Severity: Normal Priority: P5 - None Component: Installation AssignedTo: bnc-team-screening@forge.provo.novell.com ReportedBy: ajorgensen@novell.com QAContact: jsrain@novell.com Found By: --- openSUSE have chosen to leave the MBR generic as described here: http://en.opensuse.org/Bugs/grub#How_does_a_PC_boot_.2F_How_can_I_set_up_a_w... This default configuration can make it impossible to boot Windows Vista. It appears that Vista requires that it's system partition be marked active (boot). This creates an unusable situation because openSUSE also requires that it's system partition be marked active. Since only one partition may be marked active Vista cannot be used. The situation is further aggravated by the fact that using the makeactive flag in grub when chainloading will cause only Vista to be bootable if even that. In my own case Vista became unbootable every time grub was used to attempt to boot it. Some modification was made to the partition table which was correctable by using the repair function of the Vista install disk. For myself I have managed to remedy the situation by installing an MBR which allows me to choose which partition's bootloader to run, but the situation needs to be solved somehow generally. It may be that the recommendation to leave the MBR untouched is a bad one for this case. I realize that there were also valid motivations for it though. -- Configure bugmail: https://bugzilla.novell.com/userprefs.cgi?tab=email ------- You are receiving this mail because: ------- You are on the CC list for the bug.