On 10/27/2014 04:30 AM, Central Scrutinizer wrote:
Just adding a resistor to the lead will not reduce the open voltage. However, it will reduce the voltage under load. In order for that resistor to cause a voltage drop, there must be current flowing through it, which is something you don't have when the circuit is open. A decent volt meter will not draw enough current to produce a noticeable voltage drop. If you want to drop the voltage to an open circuit, you need two resistors, R1 & R2, wired in series, with one end of R1 connected to the charger and one end of R2 connected to ground. The connection between the two will then have an open circuit voltage proportional to R2/(R1+R2). There will now be a significant current through R2, which may reduce the charging capacity of the charger.
When you measure the "open voltage" with a voltmeter, the added resistance
should cause a drop in measured voltaage. I suggest you review Ohm's law. A volt meter draws virtually no current. Since it's current through a resistor that causes the voltage drop, if there's no current, there's no voltage drop.
BTW, my education is in electrical engineering. https://en.wikipedia.org/wiki/Ohm%27s_law -- To unsubscribe, e-mail: opensuse+unsubscribe@opensuse.org To contact the owner, e-mail: opensuse+owner@opensuse.org