# Mailinglist Archive: opensuse (4053 mails)

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##### Re: [SLE] AMD running too hot
• From: Linux Fan <linux_sl_ml_01@xxxxxxxxx>
• Date: Tue, 21 Aug 2001 12:52:50 -0700 (PDT)
• Message-id: <20010821195250.24929.qmail@xxxxxxxxxxxxxxxxxxxxxx>
Hi Laurence,

You are missing one crucial point, and that is you are
ignoring the impedance(Resistance) of the actual
processor involved!

v = electrical potential(voltage)
i = current
r = resistance
p = power

v = i * r
p = v * i

or with substitution,
p = i^2 * r

Now, if you believe that with higher voltage, you will
get higher power, then you should also believe the
next few lines:

Case 1
Voltage = V1
Power used = 30w
resistance(constant) = R2

Case 2
Voltage = V2 higher than V1
Power used = 35w
resistance(constant) = R2

using p = i^2 * r, you should find that the second
current is higher than the first. Current cant and
wont stay constant. If you have a different proof, I
would like to see it.

Sinan

--- Laurence Orchard <laurence@xxxxxxxxxxxxxxx> wrote:
> At 11:39 20/08/01 +0300 you scribbled:
> >Hi
> >
> >Correct... And even more so, because the fact that
> with higher core voltage
> >the rise/fall times decreases, and thus consumes
> more power, generates more
> >heat, and generate more RF- and EMI
> >
> >Jaska.
>
> Don't understand about the rise/fall times
> decreasing?
>
> Using the standard formula watts = volts * amps
> if the required power remains the same then if you
> increase the voltage the
> current must fall!
>
> if the power requirement does increase then with a
> higher voltage the
> current will not rise as high.
>
> 2 watts = 1volt * 2amps or
> 2 watts = 2volts * 1amp
>
> therefore
>
> 4watts = 1volt * 4amps or
> 4watts = 2volts * 2amps
>
>
> >Viestiss Maanantai 20. Elokuuta 2001 11:39, Mark
> Hounschell kirjoitti:
> > > Laurence Orchard wrote:
> > > > At 09:25 16/08/01 -0700 you scribbled:
> > > > >Hello Guy,
> > > > >
> > > > ><snip>
> > > > >
> > > > >Remember that increasing the core voltage to
> you CPU
> > > > >would increase the produced heat. Though, I
> don't
> > > > >think its the temperature that is causing
> your
> > > > >problem. Try e-mailing AMD and asking them if
> > > > >increasing the voltage to you cpu wouldn't in
> any way
> > > > >void your warranty since you would be running
> you CPU
> > > > >out of spec and that is not recommended.
> > > >
> > > > Increasing the core voltage does not increase
> the amount of heat produced
> > > > it should reduce it,
> > > > more volts = less amps = less current = less
> heat
> > >
> > > more volts with same impeddance = more amps
> > >
> > > 1volt into 1 ohm = 1amp
> > > 2volt into 1 ohm = 2amp
> > > 2volt into 2 ohm = 1amp
>
>
> Laurence
>
> ** if you want to know what the program really does,
> look at the code **
>
>
> laurence@xxxxxxxxxxxxxxx
>
> This Mail should NOT have an attachment, if it does
> it may have been
> created by a VIRUS
> DO NOT OPEN IT!!!
>
>
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