Mailinglist Archive: radeonhd (427 mails)

[Alex Deucher <alexdeucher@xxxxxxxxx>]

2009/5/20 Rafał Miłecki <zajec5@xxxxxxxxx>:
> W dniu 20 maja 2009 19:34 użytkownik Alex Deucher
> <alexdeucher@xxxxxxxxx> napisał:
> > 2009/5/20 Rafał Miłecki <zajec5@xxxxxxxxx>:
> > > Could you explain that one more please, so I could try to understand that?
> >
> > 0x180 is the offset of the regsiter in dwords.  0x180 * 4 = 0x600 =
> > offset in bytes since 1 dword = 4 bytes.  The register offset defines
> > the register's location relative to the start of register aperture. so
> > the register in question is 0x180 dwords from the start of the
> > aperture or 0x600 bytes.
>
> OK, understand that already, thanks.
>
> > Each register is 32 bits, so the lower two bytes are 0x4567.
>
> That was tricky part for me. I would call 0x4567 in any following way:
> a) last 2 dwords
> b) last 4 hexs
> c) last 8 bytes
> d) last 64 bits

?

> but not "two bytes". Anyway, I get this now, thanks for explaining :)

But it is 2 bytes.  The entire register is only 1 dword (32 bits or 4
bytes): 0x01234567.  You can break that down as 4 bytes:
0x01 0x23 0x45 0x67
so the lower two bytes are:
0x4567

Alex
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