-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 The Monday 2008-02-18 at 08:09 -0500, James Knott wrote:
Judging from this response and the one to Randall, I suspect it might be a good idea for you to review your EE texts. RMS is meaningless in the context of power. Sure you can do the calculation, but what does it get you? With current or voltage, RMS derives the equivalent DC value. Can you explain what you'd obtain by calculating RMS power?
The detail is that the RMS power is not equal to the product of RMS voltage times RMS amperage. That would be voltampers, not wats: there is a difference. It would be the RMS of the A·V waveform product. Ie, if V and A are sine waves, W is also a sine wave; then you can talk of the peak power, and of the RMS power. - -- Cheers, Carlos E. R. -----BEGIN PGP SIGNATURE----- Version: GnuPG v2.0.4-svn0 (GNU/Linux) iD8DBQFHuZPktTMYHG2NR9URApy0AJ0WMJ6EltOprpf5LPweX6oA6g1yIwCbBiE6 wuluWR+WGcOariZDOe6IN4c= =HW/W -----END PGP SIGNATURE-----