-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 The Sunday 2007-06-03 at 14:02 -0700, Randall R Schulz wrote:
Let me see; an 8*10 inches page at 1200 dots per inch, that's 115.2e6 pixels... calculate the memory needed.
1200 dots per inch? I thought we were talking about a home or office printer. 600dpi is more typical for today's laser printers.
I like worst case gross-overestimates :-P
Also, the imageable area is typically reduced by about .25 in. on each edge.
Furthermore, keep in mind that these are one-bit pixels.
I left that as a exercise to the reader :-p
So a reasonable calculation of the number of frame buffer bytes for an 8.5 x 11 page would be:
8 x 10.5 x 600 x 600 / 8 = 3,780,000 bytes ~ 3.6 MB
And his printer has 3MB, so that's not enough to print full page bitmaps, because you need space for the original ps, the process, perhaps converting color to gray, the result... and if it prints, it will be slow; I guess it has to go by bands. - -- Cheers, Carlos E. R. -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.5 (GNU/Linux) Comment: Made with pgp4pine 1.76 iD8DBQFGY1sqtTMYHG2NR9URAhOpAJ4r2DTkWpIJbmaX/6gWspuUqrYh6wCfUXqO TldKc4Z/oluLuQOY4tfdmPc= =wjRu -----END PGP SIGNATURE----- -- To unsubscribe, e-mail: opensuse+unsubscribe@opensuse.org For additional commands, e-mail: opensuse+help@opensuse.org