Mailinglist Archive: opensuse (3135 mails)

[Vince Oliver <vince@xxxxxxxxxxxxxxx>]

On Sat, 10 Mar 2007, Anders Johansson wrote:

> On Saturday 10 March 2007 08:39, Randall R Schulz wrote:
> > On Friday 09 March 2007 16:32, Anders Johansson wrote:
> > > ...
> > >
> > > I'm not very happy with the string tests, but I couldn't find a bash
> > > function that returned true on substring match. If anyone can think
> > > of a cleaner way of doing it, I'd love to know it
> >
> > Check out the [[ value = pattern ]] tests. There are options for both
> > glob and RE interpretation of "pattern."
>
> Cool, that works, thanks
>
> So
>
> for dir in DH*; do
>  for file in `find $dir -type f -name more\*.dat`; do
>     [[ $file =~ t\(10\|9\) ]] || head -5 $file >> $dir/list;
>  done;
> done

Thanks.  But I do not want the whole content of files in 'list' just 6th, 
7th columns and file names (as you mat read in awk command bellow)


for dir in DH* ; do
for file in `find $dir -type f -name "more*data.dat" -exec egrep -vq 
'\<t(9|10)\>' {} \; -print`; do
awk 'BEGIN{FS=","}{if(NR>1 && NR<7){ 
f=n=FILENAME;sub(/[^/]+$/,"list",f);sub(/.*\//,"",n);print $6,$7,n>>f}}' 
$file
done
done

this command works fine but filtering out lines with egrep does not work





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