Shell script problem

5 Dec 2001

      Hi all,

I am just a beginner at shell scripting, but I need to make a script which:
1) hardlinks the content of a directory into another place
2) sets up the correct permissions of files in the other place

I have to do this because the user of my system do a mess when they want to 
share some file each other.

This is what I have tried:

#!/bin/sh
#Syntax is supposed to be link.sh <directory>

case "$1" in
        --help) echo "Syntax is link.sh <dir>";
                echo "If you want to share some files only, create the dir 			
	    before this command";
                exit 0
        ;;
        *)
                export WHOAMI=`whoami`;
                mkdir /home/share/"$1"."$WHOAMI"/ ;
                ln ./"$1"/* /home/share/"$1"."$WHOAMI"/. ;
                chmod -R a+r /home/share/"$1"."$WHOAMI" ;
                chmod -R g-w /home/share/"$1"."$WHOAMI" ;
                chmod -R o-w /home/share/"$1"."$WHOAMI" ;
                chmod a+x /home/share/"$1"."$WHOAMI" ;

                #Ok, it's not very recorsive
                for i in /home/share/"$1".$WHOAMI/* ; do [ -d "$i" ] && 
				 \ chmod a+x "$i" ; done ;
                #and there is no error handling
                exit 0
        ;;

exit 0;
#############END

This script creates a mistake (syntax error near unexpected token exit).
I cant work around it, any advice?

Praise