Hi Laurence,
You are missing one crucial point, and that is you are
ignoring the impedance(Resistance) of the actual
processor involved!
v = electrical potential(voltage)
i = current
r = resistance
p = power
v = i * r
p = v * i
or with substitution,
p = i^2 * r
Now, if you believe that with higher voltage, you will
get higher power, then you should also believe the
next few lines:
Case 1
Voltage = V1
Power used = 30w
resistance(constant) = R2
Case 2
Voltage = V2 higher than V1
Power used = 35w
resistance(constant) = R2
using p = i^2 * r, you should find that the second
current is higher than the first. Current cant and
wont stay constant. If you have a different proof, I
would like to see it.
Sinan
--- Laurence Orchard
At 11:39 20/08/01 +0300 you scribbled:
Hi
Correct... And even more so, because the fact that with higher core voltage the rise/fall times decreases, and thus consumes more power, generates more heat, and generate more RF- and EMI
Jaska.
Don't understand about the rise/fall times decreasing?
Using the standard formula watts = volts * amps if the required power remains the same then if you increase the voltage the current must fall!
if the power requirement does increase then with a higher voltage the current will not rise as high.
2 watts = 1volt * 2amps or 2 watts = 2volts * 1amp
therefore
4watts = 1volt * 4amps or 4watts = 2volts * 2amps
Laurence Orchard wrote:
At 09:25 16/08/01 -0700 you scribbled:
Hello Guy,
<snip>
Remember that increasing the core voltage to you CPU would increase the produced heat. Though, I don't think its the temperature that is causing your problem. Try e-mailing AMD and asking them if increasing the voltage to you cpu wouldn't in any way void your warranty since you would be running you CPU out of spec and that is not recommended.
Increasing the core voltage does not increase
Viestiss Maanantai 20. Elokuuta 2001 11:39, Mark Hounschell kirjoitti: the amount of heat produced
it should reduce it, more volts = less amps = less current = less heat
more volts with same impeddance = more amps
1volt into 1 ohm = 1amp 2volt into 1 ohm = 2amp 2volt into 2 ohm = 1amp
Laurence
** if you want to know what the program really does, look at the code **
laurence@orchards.org.uk
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