At 11:39 20/08/01 +0300 you scribbled:
Hi
Correct... And even more so, because the fact that with higher core voltage the rise/fall times decreases, and thus consumes more power, generates more heat, and generate more RF- and EMI
Jaska.
Don't understand about the rise/fall times decreasing? Using the standard formula watts = volts * amps if the required power remains the same then if you increase the voltage the current must fall! if the power requirement does increase then with a higher voltage the current will not rise as high. 2 watts = 1volt * 2amps or 2 watts = 2volts * 1amp therefore 4watts = 1volt * 4amps or 4watts = 2volts * 2amps
Viestiss Maanantai 20. Elokuuta 2001 11:39, Mark Hounschell kirjoitti:
Laurence Orchard wrote:
At 09:25 16/08/01 -0700 you scribbled:
Hello Guy,
<snip>
Remember that increasing the core voltage to you CPU would increase the produced heat. Though, I don't think its the temperature that is causing your problem. Try e-mailing AMD and asking them if increasing the voltage to you cpu wouldn't in any way void your warranty since you would be running you CPU out of spec and that is not recommended.
Increasing the core voltage does not increase the amount of heat produced it should reduce it, more volts = less amps = less current = less heat
more volts with same impeddance = more amps
1volt into 1 ohm = 1amp 2volt into 1 ohm = 2amp 2volt into 2 ohm = 1amp
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