Mailinglist Archive: opensuse-programming (98 mails)

[Zoltan Szecsei <zoltans@xxxxxxxxxxxxxx>]

Hi Peeps,

Can I please just pick up on this thread....

If the filename has spaces in it (eg: "Full\ Length\ Movies") how can I 
get the entire filename into $i because what is happening is, on first 
iteration $i is "Full" , on 2nd it is "Length" etc...

TIA,
Zoltan



Jerry Feldman wrote:
> On Thursday 05 May 2005 2:37 am, robert guru wrote:
>
> > Hallo,
> > I m a shell scripting newbie, and i m trying to create a shell script
> > that search for some files named 'script', those files are located in the
> > subdirectory of a directory named "folder", and for each file founded, i
> > have to show the directory (full path) where  the file was founded and 
> > pipe the file to some program.
> > the script must be something like that:
> >
> > for  each file found in the subdirectory tree of "folder"
> > do
> >    "show the full path where the file was found, without the file name,
> > like /root/folder/images"
> >     enter this directory already showed ($cd directory)
> >    "pipe the file to a program"
> > done
>
> A patrick mentioned, find should work, but here is a bash script that does 
> what you want. The script is not very elegant as I threw it together. 
> In this case, sname is a variable containing the name of a file that has 
> "script" in the name. 
> #!/bin/bash
> for i in $(ls -p)
> do
>         case $i in
>                 */) cd $i; pth=$PWD;
>                 for sname in $(ls)
>                 do
>                         case $sname in
>                                 *script*) echo "$sname found in $pth";;
>                         esac
>                 done
>                 cd ..;;
>         esac
> done

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