Mailinglist Archive: opensuse-programming (33 mails)

[Prabu Subroto <prabusubroto@xxxxxxxxx>]

do you mean like this:
"
char mybuffer[];
fstream sumber("smb.conf");
if (!sumber){
    cout << "Failed in opening the 'smb.conf'
    file\n";
    exit(1);
    }
sumber >> mybuffer;
cout << mybuffer << endl;
"?

Please tell me more details. Could you give me a very
simple sample?

Thank you very much for your generousity.
--- Alan Lenton <alan@xxxxxxxxxxx> wrote:

> Prabu Subroto wrote:
> > Dear my friend.
> > 
> > I want to make a linux server administrating tool
> ( I
> > am also a beginner in GNU C++).
> > 
> > if I open the file (smb.conf) with ifstream and
> try to
> > display its content with cout, but it does not
> display
> > its content only somewhat looksline only an
> address of
> > the variable in the memory.
> > like this:
> > "
> > psubroto@vh64:~/arsip/proyek/g++/BLiSS> ./liss
> > Choose the server you would like to administrate :
> > 1. Samba Server
> > 1
> > Samba Server Administrating Menu
> > --------------------------------
> > 
> > Workgroup name :bitp
> > nama workgroup-nya : bitp
> > 0xbfffef64
> > psubroto@vh64:~/arsip/proyek/g++/BLiSS>
> > "
> > 
> > what is my mistake?
> [snip...]
> 
> > void bsamba::menu(){
> >     cout << "Samba Server Administrating Menu\n";
> >     cout << "--------------------------------\n"
> <<
> > endl;
> >     cout << "Workgroup name :";
> >     cin >> bwg;
> > 
> >     cout << "nama workgroup-nya : " << bwg <<
> endl;
> >     fstream sumber("smb.conf");
> >     if (!sumber){
> >         cout << "Failed in opening the 'smb.conf'
> > file\n";
> >         exit(1);
> >     }
> >     cout << sumber << endl;
> > }
> 
> [snip...]
> 
> What you have asked it to print out is not the file,
> but the address of 
> the stream. You need to use the stream (sumber) to
> read the file into a 
> buffer and then write the buffer out to cout :)
> 
> alan
> 



		
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