Mailinglist Archive: opensuse-programming (32 mails)

[Verdi March <cincaipatron@xxxxxxx>]

Hi,
I'd like to ask a (basic) question about operator post inc (lvalue++).
I've this code fragment:

/**************/
int y = 10;
int z;
z = y++;
cout << "z = " << z << '\n';

int x = 10;
x = x++;
cout << "x = " << x << '\n';
/**************/

The execution results in:
z = 10
x = 11

I'm confused why x became 11, because the post inc. operator has
higher precedence than assignment, so given an expressoin x = x++, 
x++ is evaluated first. The signature for post inc. is T operator++(int).
So the return value of x++ is 10 (x itself will be modified to 11), but
then the expression of x = (x++) become x = ret_val_of_x_plus_plus,
which is x = 10? Am I correct?


Regards,
Verdi

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