Alexandr Malusek wrote:

Jon Pennington writes:

...

Later on, I'll add the necessary header information, but for now, I need to strip the extra RPM version data from the file. It has a list of RPMs like this:

WindowMaker-0.64.0-63 a2ps-4.13-74 aaa_base-2001.5.22-0

But I need a list like this:

WindowMaker a2ps aaa_base

So I need a quick and dirty way to strip every line of every "-[0,9]*" and keep the rest of the name intact. It's a bit tricker since some packages don't use underscores but hyphens to seperate parts of the package name, such as alsa-devel, which means you can't just strip everything past the first hypen. Whaddayathink?

Basically, you can do it like this:

#!/bin/bash

rpm -qa | sort | while read name_ver_rev; do name_ver=${name_ver_rev%-*} name=${name_ver%-*} echo $name done

But I don't understand why you just don't print the names:

$ rpm -qa --queryformat "%{NAME}\n" | sort

That`s good. I had this problem a longer time ago, too and I did the following rpm -qa | cut -d"-" -f1 | sort But I did not know rpm has an option for this. So I learned now.... Rene

--- Alexandr Malusek wrote:

But I don't understand why you just don't print the names:

$ rpm -qa --queryformat "%{NAME}\n" | sort

This is perfect! I'll reboot shortly and re-get the package selection using this. I'd still like to see a decent way to strip a text file, but this will certainly do the task, thank you! ===== -- -=|JP|=- Hit me! - http://www.xanga.com/cowboydren/ Jon Pennington | Debian 2.3 -o) cowboydren @ yahoo . com | Auto Enthusiast /\\ Kansas City, MO, USA | ICQ UIN 69 67 29 31 _\_V __________________________________________________ Do You Yahoo!? Make a great connection at Yahoo! Personals. http://personals.yahoo.com